内容简介:Reverse a singly linked list.Example:Follow up:
Reverse a singly linked list.
Example:
Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL
Follow up:
A linked list can be reversed either iteratively or recursively. Could you implement both?
反转单链表,看到我好几年前通过的代码居然是用List遍历保存之后再倒序遍历反转,然而还RE了好几次。。。往事突然浮现在脑海,没忍住又重写了一下。
耗时0ms
class Solution {
public ListNode reverseList(ListNode head) {
ListNode cur = head, prev = null, temp = null;
while (cur != null) {
temp = cur.next;
cur.next = prev;
prev = cur;
cur = temp;
}
return prev;
}
}
以前的代码是这样的(耗时464ms):
public class Solution {
public ListNode reverseList(ListNode head) {
if(head == null || head.next == null)
return head;
ArrayList<Integer> list = new ArrayList<Integer>();
ListNode p = head;
while(p!=null) {
list.add(p.val);
p = p.next;
}
ListNode q = head;
for(int i=list.size()-1; i>=0; i--) {
q.val = list.get(i);
q = q.next;
}
return head;
}
}
以上所述就是小编给大家介绍的《LeetCode - 206. Reverse Linked List》,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对 码农网 的支持!
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