C 语言实例 - 计算两个时间段的差值 | C 语言教程

计算两个时间段的差值。

实例

#include <stdio.h> struct TIME { int seconds; int minutes; int hours; }; void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff); int main() { struct TIME startTime, stopTime, diff; printf("输入开始时间: \n"); printf("输入小时、分钟、秒："); scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds); printf("输入停止时间: \n"); printf("输入小时、分钟、秒: "); scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds); // 计算差值 differenceBetweenTimePeriod(startTime, stopTime, &diff); printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds); printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds); printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds); return 0; } void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff) { if(stop.seconds > start.seconds){ --start.minutes; start.seconds += 60; } diff->seconds = start.seconds - stop.seconds; if(stop.minutes > start.minutes){ --start.hours; start.minutes += 60; } diff->minutes = start.minutes - stop.minutes; diff->hours = start.hours - stop.hours; }

输出结果为：

输入开始时间: 
输入小时、分钟、秒：12 34 55
输入停止时间: 
输入小时、分钟、秒: 8 12 5

差值: 12:34:55 - 8:12:5 = 4:22:50

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C 语言实例 - 计算两个时间段的差值

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