C 语言实例 - 实现简单的计算器

C 语言教程 · 2019-02-20 21:57:10

实现加减乘除计算。

实例

# include <stdio.h> int main() { char operator; double firstNumber,secondNumber; printf("输入操作符 (+, -, *,): "); scanf("%c", &operator); printf("输入两个数字: "); scanf("%lf %lf",&firstNumber, &secondNumber); switch(operator) { case '+': printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber); break; case '-': printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber); break; case '*': printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber); break; case '/': printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber); break; // operator doesn't match any case constant (+, -, *, /) default: printf("Error! operator is not correct"); } return 0; }

输出结果为：

输入操作符 (+, -, *,): *
输入两个数字: 4 5
4.0 * 5.0 = 20.0

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Hackers

Steven Levy / O'Reilly Media / 2010-5-30 / USD 21.99

This 25th anniversary edition of Steven Levy's classic book traces the exploits of the computer revolution's original hackers -- those brilliant and eccentric nerds from the late 1950s through the ear......一起来看看《Hackers》这本书的介绍吧!

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namespace HelloWorld
{
    class Program
    {
        static void Main(string[] args)
        {
            System.Console.Write("Hello, World!");
        }
    }
}

C 语言实例 - 实现简单的计算器

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Hackers

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