Python基础练习100题 ( 21~ 30）

刷题继续

昨天和大家分享了前10道题，今天继续来刷21~30

Question 21:

A robot moves in a plane starting from the original point (0,0). The robot can move toward UP, DOWN, LEFT and RIGHT with a given steps. The trace of robot movement is shown as the following:

UP 5
DOWN 3
LEFT 3
RIGHT 2

The numbers after the direction are steps. Please write a program to compute the distance from current position after a sequence of movement and original point. If the distance is a float, then just print the nearest integer.

Example:

If the following tuples are given as input to the program:

UP 5
DOWN 3
LEFT 3
RIGHT 2

Then, the output of the program should be:

解法一

import  math

x,y = 0,0
while True:
    s = input().split()
    if not s:
        break
    if s[0]=='UP':                  # s[0] indicates command
        x-=int(s[1])                # s[1] indicates unit of move
    if s[0]=='DOWN':
        x+=int(s[1])
    if s[0]=='LEFT':
        y-=int(s[1])
    if s[0]=='RIGHT':
        y+=int(s[1])
                                    # N**P means N^P
dist = round(math.sqrt(x**2 + y**2))  # euclidean distance = square root of (x^2+y^2) and rounding it to nearest integer
print(dist)

Question 22:

New to Python or choosing between Python 2 and Python 3? Read Python 2 or Python 3.

Then, the output should be:

2:2
3.:1
3?:1
New:1
Python:5
Read:1
and:1
between:1
choosing:1
or:2
to:1

解法一

ss = input().split()
word = sorted(set(ss))     # split words are stored and sorted as a set

for i in word:
    print("{0}:{1}".format(i,ss.count(i)))

解法二

ss = input().split()
dict = {}
for i in ss:
    i = dict.setdefault(i,ss.count(i))   

dict = sorted(dict.items())            
                                         
for i in dict:
    print("%s:%d"%(i[0],i[1]))

解法三

from collections import Counter

ss = input().split()
ss = Counter(ss)         # returns key & frequency as a dictionary
ss = sorted(ss.items())  # returns as a tuple list

for i in ss:
    print("%s:%d"%(i[0],i[1]))

Question 23:

Write a method which can calculate square value of number

解法一

def square(num):
    return num ** 2

print(square(2))
print(square(3))

解法二

n=int(input())
print(n**2)

Question 24:

解法一

print (abs.__doc__)
print (int.__doc__)

def square(num):
    '''
 Return the square value of the input number.
 The input number must be integer.
 '''
    return num ** 2

print (square(2))
print (square.__doc__)

Question 25:

Define a class, which have a class parameter and have a same instance parameter.

解法一

class Car:
    name = "Car"

    def __init__(self,name = None):
        self.name = name

honda=Car("Honda")
print("%s name is %s"%(Car.name,honda.name))

toyota=Car()
toyota.name="Toyota"
print("%s name is %s"%(Car.name,toyota.name))

解法二

class Person:
    # Define the class parameter "name"
    name = "Person"
    
    def __init__(self, name = None):
        # self.name is the instance parameter
        self.name = name

jeffrey = Person("Jeffrey")
print ("{0} name is {1}".format(Person.name, jeffrey.name))

nico = Person()
nico.name = "Nico"
print (f"{Person.name} name is {nico.name}")

Question 26:

Define a function which can compute the sum of two numbers.

解法一

sum = lambda n1,n2 : n1 + n2      # here lambda is use to define little function as sum
print(sum(1,2))

解法二

def SumFunction(number1, number2):
    return number1 + number2

print SumFunction(1,2)

Question 27:

Define a function that can convert a integer into a string and print it in console.

解法一

def printValue(n):
    print str(n)

printValue(3)

解法二

conv = lambda x : str(x)
n = conv(10)
print(n)
print(type(n))

Question 28:

Define a function that can receive two integer numbers in string form and compute their sum and then print it in console.

解法一

def printValue(s1,s2):
    print int(s1) + int(s2)
printValue("3","4") #7

解法二

sum = lambda s1,s2 : int(s1) + int(s2)
print(sum("10","45"))      # 55

Question 29:

Define a function that can accept two strings as input and concatenate them and then print it in console.

解法一

def printValue(s1,s2):
    print s1 + s2

printValue("3","4") #34

解法二

sum = lambda s1,s2 : s1 + s2
print(sum("10","45"))        # 1045

Question 30:

Define a function that can accept two strings as input and print the string with maximum length in console. If two strings have the same length, then the function should print all strings line by line.

解法一

def printVal(s1,s2):
    len1 = len(s1)
    len2 = len(s2)
    if len1 > len2:
        print(s1)
    elif len1 < len2:
        print(s2)
    else:
        print(s1)
        print(s2)

s1,s2=input().split()
printVal(s1,s2)

源代码下载

这十道题的代码在我的github上，如果大家想看一下每道题的输出结果，可以点击以下链接下载：

• Python 21-30题

我的运行环境 Python 3.6+,如果你用的是Python 2.7版本，绝大多数不同就体现在以下3点：

• raw_input()在Python3中是input()
• print需要加括号
• fstring可以换成.format(),或者%s，%d

谢谢大家，我们下期见！希望各位朋友不要吝啬，把每道题的更高效的解法写在评论里，我们一起进步！！！