内容简介：Given n non-negative integers a1, a2, ..., an , where each representsa point at coordinate (i, ai). n vertical lines are drawn such thatthe two endpoints of line i is at (i, ai) and (i, 0). Find two lines,
Given n non-negative integers a1, a2, ..., an , where each represents
a point at coordinate (i, ai). n vertical lines are drawn such that
the two endpoints of line i is at (i, ai) and (i, 0). Find two lines,
which together with x-axis forms a container, such that the container
contains the most water.
Note: You may not slant the container and n is at least 2.
The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7].
In this case, the max area of water (blue section) the container can
contain is 49.
Example:
Input: [1,8,6,2,5,4,8,3,7] Output: 49
开始把这题想复杂了，决定最大值的只有两侧的高度，遍历的话o(n^2)的复杂度
很多状态是重复的
可以通过双指针转化为贪心问题
对于
100001
目前的状态下移动挡板只有移动矮的挡板才能可能比当前回大
public int maxArea(int[] height) {
int max=0;
int l=0;
int r=height.length-1;
while(l<r){
max=Math.max(max,Math.min(height[l],height[r])*(r-l));
if(height[l]<height[r]) l++;
else r--;
}
return max;
}
以上所述就是小编给大家介绍的《[LeetCode]11.Container With Most Water》，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对 码农网 的支持！
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