内容简介:[LeetCode]Minimum Index Sum of Two Lists
题目描述:
LeetCode 599. Minimum Index Sum of Two Lists
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.
You need to help them find out their common interest with the least list index sum . If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.
Example 1:
Input: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"] Output: ["Shogun"] Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input: ["Shogun", "Tapioca Express", "Burger King", "KFC"] ["KFC", "Shogun", "Burger King"] Output: ["Shogun"] Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Note:
- The length of both lists will be in the range of [1, 1000].
- The length of strings in both lists will be in the range of [1, 30].
- The index is starting from 0 to the list length minus 1.
- No duplicates in both lists.
题目大意:
求两个字符串列表中索引之和最小的公共串
注意:
- 列表长度范围[1, 1000]
- 字符串长度[1, 30]
- 下标范围[0, len - 1]
- 列表内无重复
解题思路:
字典(Map)
Python代码:
class Solution(object):
def findRestaurant(self, list1, list2):
"""
:type list1: List[str]
:type list2: List[str]
:rtype: List[str]
"""
dict1 = {v : i for i, v in enumerate(list1)}
minSum = len(list1) + len(list2)
ans = []
for i, r in enumerate(list2):
if r not in dict1:
continue
currSum = i + dict1[r]
if currSum < minSum:
ans = [r]
minSum = currSum
elif currSum == minSum:
ans.append(r)
return ans
以上就是本文的全部内容,希望本文的内容对大家的学习或者工作能带来一定的帮助,也希望大家多多支持 码农网
猜你喜欢:本站部分资源来源于网络,本站转载出于传递更多信息之目的,版权归原作者或者来源机构所有,如转载稿涉及版权问题,请联系我们。
An Introduction to Genetic Algorithms
Melanie Mitchell / MIT Press / 1998-2-6 / USD 45.00
Genetic algorithms have been used in science and engineering as adaptive algorithms for solving practical problems and as computational models of natural evolutionary systems. This brief, accessible i......一起来看看 《An Introduction to Genetic Algorithms》 这本书的介绍吧!