[LeetCode]Minimum Index Sum of Two Lists

栏目: 编程工具 · 发布时间: 8年前

内容简介:[LeetCode]Minimum Index Sum of Two Lists

题目描述:

LeetCode 599. Minimum Index Sum of Two Lists

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

You need to help them find out their common interest with the least list index sum . If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

Example 1:

Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".

Example 2:

Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["KFC", "Shogun", "Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).

Note:

  1. The length of both lists will be in the range of [1, 1000].
  2. The length of strings in both lists will be in the range of [1, 30].
  3. The index is starting from 0 to the list length minus 1.
  4. No duplicates in both lists.

题目大意:

求两个字符串列表中索引之和最小的公共串

注意:

  1. 列表长度范围[1, 1000]
  2. 字符串长度[1, 30]
  3. 下标范围[0, len - 1]
  4. 列表内无重复

解题思路:

字典(Map)

Python代码:

class Solution(object):
    def findRestaurant(self, list1, list2):
        """
        :type list1: List[str]
        :type list2: List[str]
        :rtype: List[str]
        """
        dict1 = {v : i for i, v in enumerate(list1)}
        minSum = len(list1) + len(list2)
        ans = []
        for i, r in enumerate(list2):
            if r not in dict1:
                continue
            currSum = i + dict1[r]
            if currSum < minSum:
                ans = [r]
                minSum = currSum
            elif currSum == minSum:
                ans.append(r)
        return ans

以上就是本文的全部内容,希望本文的内容对大家的学习或者工作能带来一定的帮助,也希望大家多多支持 码农网

查看所有标签

猜你喜欢:

本站部分资源来源于网络,本站转载出于传递更多信息之目的,版权归原作者或者来源机构所有,如转载稿涉及版权问题,请联系我们

微信小程序(开发入门及案例详解)

微信小程序(开发入门及案例详解)

李骏、边思 / 机械工业出版社 / 2017-3-1 / 59.0

本书可分为3部分,第一部分作为基础章节,介绍了第一个小程序的搭建流程,让大家能快速上手;同时对小程序框架原理进行了详细介绍,为后面学习组件、API打下基础。 第二部分对小程序组件、API进行介绍,对组件、API的使用、注意事项进行详细讲解,并给出示例代码。 最后一部分精选5个由浅入深的案例,对小程序研发进行实战讲解,涵盖了实际项目中可能涉及的技术方案和使用方法,具备很强的实战意义。 ......一起来看看 《微信小程序(开发入门及案例详解)》 这本书的介绍吧!

RGB转16进制工具
RGB转16进制工具

RGB HEX 互转工具

在线进制转换器
在线进制转换器

各进制数互转换器

RGB HSV 转换
RGB HSV 转换

RGB HSV 互转工具