内容简介:[LeetCode]Tag Validator
题目描述:
Given a string representing a code snippet, you need to implement a tag validator to parse the code and return whether it is valid. A code snippet is valid if all the following rules hold:
- The code must be wrapped in a valid closed tag . Otherwise, the code is invalid.
-
A closed tag
(not necessarily valid) has exactly the following format :
<TAG_NAME>TAG_CONTENT</TAG_NAME>
. Among them,<TAG_NAME>
is the start tag, and</TAG_NAME>
is the end tag. The TAG_NAME in start and end tags should be the same. A closed tag is valid if and only if the TAG_NAME and TAG_CONTENT are valid. -
A valid
TAG_NAME
only contain upper-case letters , and has length in range [1,9]. Otherwise, theTAG_NAME
is invalid . -
A valid
TAG_CONTENT
may contain other valid closed tags , cdata and any characters (see note1) EXCEPT unmatched<
, unmatched start and end tag, and unmatched or closed tags with invalid TAG_NAME. Otherwise, theTAG_CONTENT
is invalid . - A start tag is unmatched if no end tag exists with the same TAG_NAME, and vice versa. However, you also need to consider the issue of unbalanced when tags are nested.
-
A
<
is unmatched if you cannot find a subsequent>
. And when you find a<
or</
, all the subsequent characters until the next>
should be parsed as TAG_NAME (not necessarily valid). -
The cdata has the following format :
<![CDATA[CDATA_CONTENT]]>
. The range ofCDATA_CONTENT
is defined as the characters between<![CDATA[
and the first subsequent]]>
. -
CDATA_CONTENT
may contain any characters . The function of cdata is to forbid the validator to parseCDATA_CONTENT
, so even it has some characters that can be parsed as tag (no matter valid or invalid), you should treat it as regular characters .
Valid Code Examples:
Input: "<DIV>This is the first line <![CDATA[<div>]]></DIV>" Output: True Explanation: The code is wrapped in a closed tag : <DIV> and </DIV>. The TAG_NAME is valid, the TAG_CONTENT consists of some characters and cdata. Although CDATA_CONTENT has unmatched start tag with invalid TAG_NAME, it should be considered as plain text, not parsed as tag. So TAG_CONTENT is valid, and then the code is valid. Thus return true. Input: "<DIV>>> ![cdata[]] <![CDATA[<div>]>]]>]]>>]</DIV>" Output: True Explanation: We first separate the code into : start_tag|tag_content|end_tag. start_tag -> "<DIV>" end_tag -> "</DIV>" tag_content could also be separated into : text1|cdata|text2. text1 -> ">> ![cdata[]] " cdata -> "<![CDATA[<div>]>]]>", where the CDATA_CONTENT is "<div>]>" text2 -> "]]>>]" The reason why start_tag is NOT "<DIV>>>" is because of the rule 6. The reason why cdata is NOT "<![CDATA[<div>]>]]>]]>" is because of the rule 7.
Invalid Code Examples:
Input: "<A> <B> </A> </B>" Output: False Explanation: Unbalanced. If "<A>" is closed, then "<B>" must be unmatched, and vice versa. Input: "<DIV> div tag is not closed <DIV>" Output: False Input: "<DIV> unmatched < </DIV>" Output: False Input: "<DIV> closed tags with invalid tag name <b>123</b> </DIV>" Output: False Input: "<DIV> unmatched tags with invalid tag name </1234567890> and <CDATA[[]]> </DIV>" Output: False Input: "<DIV> unmatched start tag <B> and unmatched end tag </C> </DIV>" Output: False
Note:
-
For simplicity, you could assume the input code (including the any characters
mentioned above) only contain
letters
,digits
,'<'
,'>'
,'/'
,'!'
,'['
,']'
and' '
.
题目大意:
给定字符串判断是否为有效标签
整个字符串应为一个闭合标签
闭合标签的格式为<TAG_NAME>TAG_CONTENT</TAG_NAME>,其中<TAG_NAME>为标签头,</TAG_NAME>为标签尾,TAG_CONTENT为标签内容。
TAG_NAME只应当包含大写字母,长度1-9
TAG_CONTENT可包含其他有效的闭合标签,cdata以及其他有效字符,不可以包含失配的'<'、标签头和标签尾
标签头如果没有同名标签尾相互匹配,即为失配,反之亦然。然而,同时还需要考虑嵌套标签的匹配问题。
'<'如果没有'>'相互匹配,即视为失配。当遇到'<'或者'</'时,到下一个'>'之前的子串视为TAG_NAME(不一定有效)
cdata格式为:<![CDATA[CDATA_CONTENT]]>。CDATA_CONTENT为<![CDATA[与第一个]]>之间的部分。
CDATA_CONTENT可以包含任意字符。cdata的目的是防止校验器解析CDATA_CONTENT,因此即使其中包含的字符可以解析为标签,也还是将其视为普通字符。
解题思路:
栈(Stack)
可以参考括号匹配的解题思路。
Python代码:
class Solution(object): def isValid(self, code): """ :type code: str :rtype: bool """ tagStack = [] while code: if code.startswith('<![CDATA['): #CDATA if not tagStack: return False nextIdx = code.find(']]>') if nextIdx == -1: return False code = code[nextIdx + 3:] elif code.startswith('</'): nextIdx = code.find('>') if nextIdx == -1: return False tagName = code[2: nextIdx] if not tagStack or tagStack.pop()!= tagName: return False code = code[nextIdx + 1:] if not tagStack: return not code elif code.startswith('<'): nextIdx = code.find('>') if nextIdx == -1: return False tagName = code[1: nextIdx] if not re.match('^[A-Z]{1,9}$', tagName): return False tagStack.append(tagName) code = code[nextIdx + 1:] elif not tagStack: return False else: code = code[1:] return not tagStack
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