【LeetCode】74. Search a 2D Matrix

内容简介：【LeetCode】74. Search a 2D Matrix

问题描述

https://leetcode.com/problems/search-a-2d-matrix/#/description

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

• Integers in each row are sorted from left to right.
• The first integer of each row is greater than the last integer of the previous row. For example,

Consider the following matrix:

[
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]

Given target = 3 , return true .

算法

从左上角开始，一行一行地进行搜索，如果这一行的最后一个数小于 target ，那就移到下一行；否则，就在这一行搜索 target

参考自： https://discuss.leetcode.com/topic/29159/java-clear-solution

算法

public boolean searchMatrix(int[][] matrix, int target) {  
            if(matrix == null || matrix.length == 0) return false;
            int i = 0, j = matrix[0].length - 1;
            while(i<matrix.length && j >= 0) {
                if(matrix[i][j] == target) {
                    return true;
                } else if(matrix[i][j] < target) {
                    i++;
                } else {
                    j--;
                }
            }
            return false;
        }

转载请注明出处

：

http://www.zgljl2012.com/leetcode-74-search-a-2d-matrix/

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持 码农网

查看所有标签

猜你喜欢:

• 【LeetCode】74. Search a 2D Matrix
• LeetCode 74. Search a 2D Matrix

本站部分资源来源于网络，本站转载出于传递更多信息之目的，版权归原作者或者来源机构所有，如转载稿涉及版权问题，请联系我们。