LeetCode36.有效的数独 JavaScript

栏目: 编程工具 · 发布时间: 6年前

内容简介:判断一个上图是一个部分填充的有效的数独。

判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。

  • 数字 1-9 在每一行只能出现一次。
  • 数字 1-9 在每一列只能出现一次。
  • 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。

LeetCode36.有效的数独 JavaScript

上图是一个部分填充的有效的数独。

数独部分空格内已填入了数字,空白格用 '.' 表示。

示例 1:

输入:

[
  ["5","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]

输出: true

示例 2:

输入:

[
  ["8","3",".",".","7",".",".",".","."],
  ["6",".",".","1","9","5",".",".","."],
  [".","9","8",".",".",".",".","6","."],
  ["8",".",".",".","6",".",".",".","3"],
  ["4",".",".","8",".","3",".",".","1"],
  ["7",".",".",".","2",".",".",".","6"],
  [".","6",".",".",".",".","2","8","."],
  [".",".",".","4","1","9",".",".","5"],
  [".",".",".",".","8",".",".","7","9"]
]

输出: false
解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。

但由于位于左上角的` 3x3` 宫内有两个 `8` 存在, 因此这个数独是无效的。

说明:

一个有效的数独(部分已被填充)不一定是可解的。

只需要根据以上规则,验证已经填入的数字是否有效即可。

给定数独序列只包含数字 1-9 和字符 '.'

给定数独永远是 9x9 形式的。

答案参考:

/**
 * @param {character[][]} board
 * @return {boolean}
 */

var isValidSudoku = function(board) {
//   检查每一行
  for (let arr of board) {            
    let row = []
    for (let c of arr) {
      if (c !== '.') row.push(c);
    }
    let set = new Set(row)
    if (set.size !== row.length) return false;
  }
  
//   检查每一列
  for (let i = 0; i < 9; i++) {
    let col = []
    board.map( arr => {
      if (arr[i] !== '.') col.push(arr[i])
    })
    let set = new Set(col)
    if (set.size !== col.length) return false;
  }
  
//   检查每个小方块
  for (let x = 0; x < 9; x += 3) {
    for (let y = 0; y < 9; y += 3) {
      let box = []
      for (let a = x; a < 3 + x; a ++) {
        for (let b = y; b < 3 + y; b ++) {
          if (board[a][b] !== '.') box.push(board[a][b])
        }
      }
      let set = new Set(box)
      if (set.size !== box.length) return false
    }
  }
  
  return true
};

LeetCode36.有效的数独 JavaScript


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