58. Length of Last Word

栏目: Java · 发布时间: 6年前

内容简介:Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.If the last word does not exist, return 0.Note: A word is defined as a character sequence consists of non-space characters

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:
Input: "Hello World"
Output: 5

难度:easy

题目:

给定字符串包含大小写字母和空格,返回最后一个单词的长度。

如果最后一个单词不存在,则返回0.

Runtime: 3 ms, faster than 62.11% of Java online submissions for Length of Last Word.

Memory Usage: 21.5 MB, less than 96.23% of Java online submissions for Length of Last Word.

public class Solution {
    public int lengthOfLastWord(String s) {
        if (null == s || s.trim().isEmpty()) {
            return 0;
        }
        s = s.trim();
        int wordLength = 0;
        for (int i = s.length() - 1; i >= 0; i--) {
            if (s.charAt(i) == ' ') {
                return wordLength;
            } else {
                wordLength++;
            }
        }
        
        return wordLength;
    }
}

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持 码农网

查看所有标签

猜你喜欢:

本站部分资源来源于网络,本站转载出于传递更多信息之目的,版权归原作者或者来源机构所有,如转载稿涉及版权问题,请联系我们

Introduction to the Design and Analysis of Algorithms

Introduction to the Design and Analysis of Algorithms

Anany Levitin / Addison Wesley / 2011-10-10 / USD 117.00

Based on a new classification of algorithm design techniques and a clear delineation of analysis methods, Introduction to the Design and Analysis of Algorithms presents the subject in a coherent a......一起来看看 《Introduction to the Design and Analysis of Algorithms》 这本书的介绍吧!

UNIX 时间戳转换
UNIX 时间戳转换

UNIX 时间戳转换

正则表达式在线测试
正则表达式在线测试

正则表达式在线测试

HSV CMYK 转换工具
HSV CMYK 转换工具

HSV CMYK互换工具