golang顺时针打印矩阵

题目描述

输入一个矩阵，按照从外向里以顺时针的顺序依次打印出每一个数字，例如，如果输入如下4 X 4矩阵： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

package main

import "fmt"

func main() {
    //s := [][]int{{1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12}, {13, 14, 15, 16}}
    //s := [][]int{{1}, {2}, {3}, {4}}
    //s := [][]int{{1, 2, 3, 4}, {5, 6, 7, 8}}
    s := [][]int{{1, 2}, {5, 6}, {9, 10}, {13, 14}}

    printMatrix(s)
}
func printMatrix(s [][]int) {
    if s == nil {
        fmt.Println("切片为空，无法打印")
    }
    bex, bey := 0, 0
    hang := len(s) - 1
    lie := len(s[0]) - 1
    if hang == 0 {
        for _, v := range s[0] {
            fmt.Println(v)
        }
        return
    }
    if lie == 0 {
        for _, v := range s {
            fmt.Println(v[0])
        }
        return
    }
    for bex <= hang && bey <= lie {
        ax, ay := bex, bey
        for ay < lie {
            fmt.Println(s[ax][ay])
            ay++
        }
        for ax < hang {
            fmt.Println(s[ax][ay])
            ax++
        }
        for ay > bey {
            fmt.Println(s[ax][ay])
            ay--
        }
        for ax > bex {
            fmt.Println(s[ax][ay])
            ax--
        }
        bex++
        bey++
        hang--
        lie--
    }
}