c# – 如何序列化NHibernate映射对象的所有属性？

返回.它只是序列化对象的NHibernate映射属性……任何人都有一些洞察力？似乎Web方法实际上是序列化NHibernate代理而不是我的类.我尝试过使用[XMLInclude]和[XMLElement],但属性仍然没有序列化.我有一种非常糟糕的hackish方式绕过这个,但我想知道是否有更好的方法！

像这样的东西：

<?xml version="1.0" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="StoryManager" assembly="StoryManager">
  <class name="Graphic" table="graphics" lazy="false">
    <id name="Id" column="id" type="int" unsaved-value="0" >
      <generator class="identity"/>
    </id>

    <property name="Assigned" />
    <property name="Due" />
    <property name="Completed" />
    <property name="UglyHack" insert="false" update="false" />


    <many-to-one name="Parent" class="Story" column="story_id"/>

  </class>
</hibernate-mapping>

public class Graphic
{
    private int m_id;
    public virtual int Id
    {
        get { return m_id; }
        set { m_id = value; }
    }

    private DateTime? m_assigned;
    public virtual DateTime? Assigned
    {
        get { return m_assigned; }
        set { m_assigned = value; }
    }

    private DateTime? m_due;
    public virtual DateTime? Due
    {
        get { return m_due; }
        set { m_due = value; }
    }

    private DateTime? m_completed;
    public virtual DateTime? Completed
    {
        get { return m_completed; }
        set { m_completed = value; }
    }

    public bool UglyHack
    {
        get { return m_due < m_completed; } // return something besides a real mapped variable
        set {} // trick NHibernate into thinking it's doing something
    }
}

这显然无法编写代码.如果我没有那里的“假”映射(UglyHack属性),那么该属性将不会被序列化.现在我正在研究使用(数据)传输对象,并可能使用反射…