encoding – 如何对NSString进行URL编码

栏目: IOS · 发布时间: 6年前

内容简介：翻译自：https://stackoverflow.com/questions/15443040/how-to-url-encode-a-nsstring

我试图url编码一个字符串,但NSURLConnection失败,因为’坏网址’.这是我的网址：

NSString *address = mp.streetAddress;
    NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *cityState= mp.cityState;
    NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", encodedAddress, encodedCityState];
    NSURL *url = [NSURL URLWithString:fullAddressURL];

以下是API调用URL的示例：

下面是调用API的地址匹配“2114 Bigelow Ave”,“Seattle,WA”的地址的示例：

http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA

由于某种原因,此URL无法连接.有人可以帮我吗？

您必须先编码fullAddressURL,然后再将其发送到NSURL,而不是编码地址& cityState个别.

NSString *address = @"2114 Bigelow Ave";
//NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *cityState= @"Seattle, WA";
// NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", address, cityState];
fullAddressURL = [fullAddressURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(@"fullAddressURL: %@",fullAddressURL);

NSURL *url = [NSURL URLWithString:fullAddressURL];

我测试了上面的代码,它给出了与给定链接相同的输出http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=\u0026lt;ZWSID\u0026gt;\u0026amp;address=2114 Bigelow Ave& citystatezip = Seattle ,华盛顿州

翻译自：https://stackoverflow.com/questions/15443040/how-to-url-encode-a-nsstring

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