php – 如何使Laravel为JSON REST API返回自定义错误

我正在开发某种RESTful API.发生一些错误时,我会抛出一个App :: abort($code,$message)错误.

问题是：我希望他用键“代码”和“消息”抛出一个json形成的数组,每个数组都包含上述数据.

Array
(
    [code] => 401
    [message] => "Invalid User"
)

有没有人知道是否可能,如果是,我该怎么做？

去你的app / start / global.php.

这将将401和404的所有错误转换为自定义json错误,而不是Whoops stacktrace.加这个：

App::error(function(Exception $exception, $code)
{
    Log::error($exception);

    $message = $exception->getMessage();

    // switch statements provided in case you need to add
    // additional logic for specific error code.
    switch ($code) {
        case 401:
            return Response::json(array(
                    'code'      =>  401,
                    'message'   =>  $message
                ), 401);
        case 404:
            $message            = (!$message ? $message = 'the requested resource was not found' : $message);
            return Response::json(array(
                    'code'      =>  404,
                    'message'   =>  $message
                ), 404);        
    }

});

这是处理此错误的众多选项之一.

制作API最好创建自己的帮助器,如Responser :: error(400,’damn’),扩展了Response类.

有点像：

public static function error($code = 400, $message = null)
{
    // check if $message is object and transforms it into an array
    if (is_object($message)) { $message = $message->toArray(); }

    switch ($code) {
        default:
            $code_message = 'error_occured';
            break;
    }

    $data = array(
            'code'      => $code,
            'message'   => $code_message,
            'data'      => $message
        );

    // return an error
    return Response::json($data, $code);
}