内容简介:Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.Example 1:Input:
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.
Example 1:
Input:
5
/ 3 6
/ 2 4 7
Target = 9
Output: True
Example 2:
Input:
5
/ 3 6
/ 2 4 7
Target = 28
Output: False
之前想到全部为结点加上parent,然后求它们的前驱后继,但这样时间不够。
然后直接通过中序遍历,将BST 变成数组,二分求值了。
var findTarget = function(root, k) { var array = [] toArray(root, array) var low = 0, high = array.length -1 while(low < high){ var ret = array[low] + array[high] var diff = ret - k; if(diff === 0){ return true }else if(diff > 0){//值比较大 high-- }else { low++ } } return false }; function toArray(root, array){ root.left && toArray(root.left, array) array[array.length ] = root.val; root.right && toArray(root.right, array) }
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