内容简介:Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.Example 1:Input:
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.
Example 1:
Input:
5
/ 3 6
/ 2 4 7
Target = 9
Output: True
Example 2:
Input:
5
/ 3 6
/ 2 4 7
Target = 28
Output: False
之前想到全部为结点加上parent,然后求它们的前驱后继,但这样时间不够。
然后直接通过中序遍历,将BST 变成数组,二分求值了。
var findTarget = function(root, k) {
var array = []
toArray(root, array)
var low = 0, high = array.length -1
while(low < high){
var ret = array[low] + array[high]
var diff = ret - k;
if(diff === 0){
return true
}else if(diff > 0){//值比较大
high--
}else {
low++
}
}
return false
};
function toArray(root, array){
root.left && toArray(root.left, array)
array[array.length ] = root.val;
root.right && toArray(root.right, array)
}
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