Grassmann.jl A\b 3x faster than Julia's StaticArrays.jl

栏目: IT技术 · 发布时间: 5年前

内容简介:In this algebra, it’s possible to compute on a mesh of arbitrary 5 dimensionalAdditionally, inProgramming the

In this algebra, it’s possible to compute on a mesh of arbitrary 5 dimensional conformal geometric algebra simplices, which can be represented by a bundle of nested dyadic tensors.

julia> using Grassmann, StaticArrays; basis"+-+++"
(⟨+-+++⟩, v, v₁, v₂, v₃, v₄, v₅, v₁₂, v₁₃, v₁₄, v₁₅, v₂₃, v₂₄, v₂₅, v₃₄, v₃₅, v₄₅, v₁₂₃, v₁₂₄, v₁₂₅, v₁₃₄, v₁₃₅, v₁₄₅, v₂₃₄, v₂₃₅, v₂₄₅, v₃₄₅, v₁₂₃₄, v₁₂₃₅, v₁₂₄₅, v₁₃₄₅, v₂₃₄₅, v₁₂₃₄₅)

julia> value(rand(Chain{V,1,Chain{V,1}}))
5-element StaticArrays.SArray{Tuple{5},Chain{⟨+-+++⟩,1,  ,253} where 253 where   ,1,5} with indices SOneTo(5):
   -0.33459594357756073v₁ - 0.3920064467082769v₂ - 0.575474920388841v₃ + 0.6150287650825268v₄ - 0.7568209093000915v₅
  -0.7402635950699139v₁ - 0.9303076362461833v₂ + 0.9729806462365271v₃ - 0.8514563480551867v₄ + 0.09906887873006287v₅
  -0.7456570397821101v₁ - 0.6497560949330929v₂ + 0.4756585550844967v₃ - 0.31169948016530347v₄ - 0.9355928499340793v₅
   -0.4555014543082292v₁ + 0.712268225360094v₂ - 0.7500443783398549v₃ - 0.36349628003234713v₄ + 0.5005769037801056v₅
 -0.07402971220645727v₁ + 0.19911765119918146v₂ - 0.4980618129231722v₃ - 0.7728564279829087v₄ + 0.9165735719353756v₅

julia> A = Chain{V,1}(rand(SMatrix{5,5}))
(0.9244801277294266v₁ + 0.029444337884018346v₂ + 0.745495522394158v₃ + 0.6695874677964055v₄ + 0.4998003712198389v₅)v₁ + (0.5423877012973404v₁ + 0.30112324458605655v₂ + 0.9530587650033631v₃ + 0.2706004745612134v₄ + 0.37762612797501616v₅)v₂ + (0.7730171467954035v₁ + 0.019660709510785912v₂ + 0.39119534821037494v₃ + 0.9403026278575068v₄ + 0.07545094732793833v₅)v₃ + (0.7184128110093908v₁ + 0.6295740775044767v₂ + 0.5179035493253021v₃ + 0.039081667453648716v₄ + 0.3719284661613145v₅)v₄ + (0.5033657705978616v₁ + 0.41183905359914386v₂ + 0.7761548051732969v₃ + 0.07635587137916744v₄ + 0.5582934197259402v₅)v₅

Additionally, in Grassmann.jl we prefer the nested usage of pure ChainBundle parametric types for large re-usable global cell geometries, from which local dyadics can be selected.

Programming the A\b method is straight forward with some Julia language metaprogramming and Grassmann.jl by first instantiating some Cramer symbols

Base.@pure function Grassmann.Cramer(N::Int)
    x,y = SVector{N}([Symbol(:x,i) for i ∈ 1:N]),SVector{N}([Symbol(:y,i) for i ∈ 1:N])
    xy = [:(($(x[1+i]),$(y[1+i])) = ($(x[i])∧t[$(1+i)],t[end-$i]∧$(y[i]))) for i ∈ 1:N-1]
    return x,y,xy
end

These are exterior product variants of the Cramer determinant symbols ( N! times N -simplex hypervolumes), which can be combined to directly solve a linear system:

@generated function Base.:\(t::Chain{V,1,<:Chain{V,1}},v::Chain{V,1}) where V
    N = ndims(V)-1 # paste this into the REPL for faster eval
    x,y,xy = Grassmann.Cramer(N)
    mid = [:($(x[i])∧v∧$(y[end-i])) for i ∈ 1:N-1]
    out = Expr(:call,:SVector,:(v∧$(y[end])),mid...,:($(x[end])∧v))
    return Expr(:block,:((x1,y1)=(t[1],t[end])),xy...,
        :(Chain{V,1}(getindex.($(Expr(:call,:./,out,:(t[1]∧$(y[end])))),1))))
end

Which results in the following highly efficient @generated code for solving the linear system,

(x1, y1) = (t[1], t[end])
(x2, y2) = (x1 ∧ t[2], t[end - 1] ∧ y1)
(x3, y3) = (x2 ∧ t[3], t[end - 2] ∧ y2)
(x4, y4) = (x3 ∧ t[4], t[end - 3] ∧ y3)
Chain{V, 1}(getindex.(SVector(v ∧ y4, (x1 ∧ v) ∧ y3, (x2 ∧ v) ∧ y2, (x3 ∧ v) ∧ y1, x4 ∧ v) ./ (t[1] ∧ y4), 1))

Benchmarks with that algebra indicate a 3x faster performance than SMatrix for applying A\b to bundles of dyadic elements.

julia> @btime $(rand(SMatrix{5,5},10000)).\Ref($(SVector(1,2,3,4,5)));
  2.588 ms (29496 allocations: 1.44 MiB)

julia> @btime $(Chain{V,1}.(rand(SMatrix{5,5},10000))).\$(v1+2v2+3v3+4v4+5v5);
  808.631 μs (2 allocations: 390.70 KiB)

julia> @btime $(SMatrix(A))\$(SVector(1,2,3,4,5))
  150.663 ns (0 allocations: 0 bytes)
5-element SArray{Tuple{5},Float64,1,5} with indices SOneTo(5):
 -4.783720495603508
  6.034887114999602
  1.017847212237964
  6.379374861538397
 -4.158116538111051

julia> @btime $A\$(v1+2v2+3v3+4v4+5v5)
  72.405 ns (0 allocations: 0 bytes)
-4.783720495603519v₁ + 6.034887114999605v₂ + 1.017847212237964v₃ + 6.379374861538393v₄ - 4.1581165381110505v₅

Such a solution is not only more efficient than Julia’s StaticArrays.jl method for SMatrix , but is also useful to minimize allocations in Grassmann.jl finite element assembly.

Similarly, the Cramer symbols can also be manipulated to invert the linear system or for determining whether a point is within a simplex.

julia> using Grassmann; basis"3"
(⟨+++⟩, v, v₁, v₂, v₃, v₁₂, v₁₃, v₂₃, v₁₂₃)

julia> T = Chain{V,1}(Chain(v1),v1+v2,v1+v3)
(1v₁ + 0v₂ + 0v₃)v₁ + (1v₁ + 1v₂ + 0v₃)v₂ + (1v₁ + 0v₂ + 1v₃)v₃

julia> barycenter(T) ∈ T, (v1+v2+v3) ∈ T
(true, false)

There are multiple equivalent ways of computing the same results using the and : dyadic products.

julia> T\barycenter(T) == inv(T)⋅barycenter(T)
true

julia> sqrt(T:T) == norm(SMatrix(T))
true

The following Makie.jl streamplot was generated with the Grassmann.Cramer method and interpolated from Nedelec edges of a Maxwell finite element solution.

More info about these examples is at https://grassmann.crucialflow.com/dev/tutorials/dyadic-tensors

Hermann Grassmann was the inventor of linear algebra as we know it today.


以上所述就是小编给大家介绍的《Grassmann.jl A\b 3x faster than Julia's StaticArrays.jl》,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对 码农网 的支持!

查看所有标签

猜你喜欢:

本站部分资源来源于网络,本站转载出于传递更多信息之目的,版权归原作者或者来源机构所有,如转载稿涉及版权问题,请联系我们

Ruby on Rails敏捷开发最佳实践

Ruby on Rails敏捷开发最佳实践

李刚 / 电子工业出版社 / 2008-4 / 79.80元

《Ruby on Rails敏捷开发最佳实践》适用于正在使用Ruby On Rails进行应用开发的开发人员、渴望了解Ruby On Rails框架的开发人员,尤其适合有初步的Java EE开发经验,想从Java EE平台过渡到Ruby On Rails开发平台的开发者。 Ruby On Rails框架一经推出,立即引起B/S结构应用开发领域革命性的变化:开发者无需理会架构,只需要按Rail......一起来看看 《Ruby on Rails敏捷开发最佳实践》 这本书的介绍吧!

Base64 编码/解码
Base64 编码/解码

Base64 编码/解码

MD5 加密
MD5 加密

MD5 加密工具